3z(z^2+2)-2(z-2)+2z+1=

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Solution for 3z(z^2+2)-2(z-2)+2z+1= equation: 


Simplifying
3z(z2 + 2) + -2(z + -2) + 2z + 1 = 0

Reorder the terms:
3z(2 + z2) + -2(z + -2) + 2z + 1 = 0
(2 * 3z + z2 * 3z) + -2(z + -2) + 2z + 1 = 0
(6z + 3z3) + -2(z + -2) + 2z + 1 = 0

Reorder the terms:
6z + 3z3 + -2(-2 + z) + 2z + 1 = 0
6z + 3z3 + (-2 * -2 + z * -2) + 2z + 1 = 0
6z + 3z3 + (4 + -2z) + 2z + 1 = 0

Reorder the terms:
4 + 1 + 6z + -2z + 2z + 3z3 = 0

Combine like terms: 4 + 1 = 5
5 + 6z + -2z + 2z + 3z3 = 0

Combine like terms: 6z + -2z = 4z
5 + 4z + 2z + 3z3 = 0

Combine like terms: 4z + 2z = 6z
5 + 6z + 3z3 = 0

Solving
5 + 6z + 3z3 = 0

Solving for variable 'z'.

The solution to this equation could not be determined.

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